Sunday, November 17, 2019

Money Bill Denominator in C

I wrote this program using a C programming language that will ask the user an amount in the Philippines Peso currency and then the program will count the number of bill denominators in the given amount from our user.

I am currently accepting programming work, IT projects, school and application development, programming projects, thesis and capstone projects, IT consulting work, computer tutorials, and web development work kindly contact me in the following email address for further details.  If you want to advertise on my website kindly contact me also in my email address also. Thank you.

My email address is the following jakerpomperada@gmail.com, jakerpomperada@aol.com, and jakerpomperada@yahoo.com.

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Here in Bacolod City, Negros Occidental I also accepting computer repair, networking and Arduino Project development at a very affordable price.

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Thank you very much for your help and support.





Sample Program Output


Program Listing

money.c

/* money.c
   Jake R. Pomperada,MAED-IT
   November 17, 2019
   Bacolod City, Negros Occidental
*/

#include <stdio.h>

int main()
{
    int amount=0;
    
    int note1000=0,note500=0, note100=0, note50=0, note20=0, note10=0, note5=0, note2=0, note1=0;
    

    note1000=note500 = note100 = note50 = note20 = note10 = note5 = note2 = note1 = 0;

    printf("\n\n");
    printf("\tMoney Denominator in C");
    printf("\n\n");
    printf("\tGive an Amount PHP : ");
    scanf("%d", &amount);


    if(amount >= 1000)
    {
        note1000 = amount/1000;
        amount -= note1000 * 1000;
    }

    if(amount >= 500)
    {
        note500 = amount/500;
        amount -= note500 * 500;
    }
    if(amount >= 100)
    {
        note100 = amount/100;
        amount -= note100 * 100;
    }
    if(amount >= 50)
    {
        note50 = amount/50;
        amount -= note50 * 50;
    }
    if(amount >= 20)
    {
        note20 = amount/20;
        amount -= note20 * 20;
    }
    if(amount >= 10)
    {
        note10 = amount/10;
        amount -= note10 * 10;
    }
    if(amount >= 5)
    {
        note5 = amount/5;
        amount -= note5 * 5;
    }
    if(amount >= 2)
    {
        note2 = amount /2;
        amount -= note2 * 2;
    }
    if(amount >= 1)
    {
        note1 = amount;
    }

    printf("\n\n");
    printf("\tTotal number of notes = \n");
    printf("\n");
     printf("\t1000 = %d\n", note1000);
    printf("\t500 = %d\n", note500);
    printf("\t100 = %d\n", note100);
    printf("\t50 = %d\n", note50);
    printf("\t20 = %d\n", note20);
    printf("\t10 = %d\n", note10);
    printf("\t5 = %d\n", note5);
    printf("\t2 = %d\n", note2);
    printf("\t1 = %d\n", note1);
    printf("\n\n");
    printf("\tEnd of Program");
}



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