List a Number Without Using a Loop in C++

Here is a code that I wrote a very long time ago that will list a number from 1 to 50 without using any looping statement in C++ but rather it uses if statement.

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Program Listing

#include <iostream>

#include <stdlib.h>

using namespace std;

int print(int num){

    if(num<=50){

         cout << " " << num << " ";

          print(num+1);

    }

}

int main(){

    int num = 1;

    cout << "\nList of Numbers Without Using a Loop in C++";

    cout <<"\n\n";

    print(num);

    cout <<"\n\n";

    cout << "\nEnd of Program";

    cout <<"\n\n";

    system("pause");

}