Arrays and Pointers in C++

Hi there here is a sample program that shows you how to use one dimensional array and pointers in C++ this code I used it before in my programming class in C++ in college. The code is very short and easy to understand. Thank you.

My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 

My mobile number here in the Philippines is 09173084360.

Program Listing

#include <iostream>

using namespace std;

int add(int &a,int &b, int &c, int &d)

{

    return(a+b+c+d);

}

main() {

    int val[4];

    val[0] = 2;

    val[1] = 4;

    val[2] = 6;

    val[3] = 8;

    cout << "The sum of "

       << val[0] <<  ","

      << val[1] <<  ","

      << val[2] <<  ","

      << val[3] <<  " is "

      << add(val[0],val[1],val[2],val[3])

      << ".";

      cout << "\n\n";

      system("pause");

}

Palindrome Checker in Visual Basic NET

Here is another simple program that I wrote using Visual Basic NET to ask the user to give a string and then our program will check and determine if the given string is a Palindrome or Not a Palindrome. The code is very simple and easy to understand. I hope you will learn from this one. Thank  you.

My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 

My mobile number here in the Philippines is 09173084360.

Sample Program Output

Program Listing

Public Class Form1

    Public Function StrPalindrome(ByVal sSource As String) As String

        Dim s1 As String

        Dim s2 As String

        s1 = TextBox1.Text

        s2 = StrReverse(s1)

        If (s1 = s2) Then

            MessageBox.Show("The give word " & UCase(TextBox1.Text) & " is a Palindrome.")

        Else

            MessageBox.Show("The give word " & UCase(TextBox1.Text) & " is Not a Palindrome.")

        End If

    End Function

    Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click

        End

    End Sub

    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click

        Dim str_word As String

        str_word = StrPalindrome(TextBox1.Text)

    End Sub

    Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click

        TextBox1.Text = ""

        TextBox1.Focus()

    End Sub

End Class

Palindrome Checker in Visual Basic 6

Here is another simple program that I wrote using Visual Basic 6 to ask the user to give a string and then our program will check and determine if the given string is a Palindrome or Not a Palindrome. The code is very simple and easy to understand. I hope you will learn from this one. Thank  you.

My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 

My mobile number here in the Philippines is 09173084360.

Sample Program Output

Program Listing

Private Sub Command1_Click()

Dim str_word As String

str_word = StrPalindrome(Form1.Text1.Text)

End Sub

Private Sub Command2_Click()

End

End Sub

Private Sub Form_Load()

Form1.Show

End Sub

Public Function StrPalindrome(ByVal sSource As String) As String

    Dim l As Long, strRev As String

    Dim ab() As Byte

    ab = StrConv(sSource, vbFromUnicode)

    For l = UBound(ab) To 0 Step -1

        strRev = strRev & Chr$(ab(l))

    Next l

    If strRev = sSource Then

        MsgBox "The give word " & UCase(Text1.Text) & " is a Palindrome."

    Else

         MsgBox "The give word " & UCase(Text1.Text) & " is Not a Palindrome."

    End If

End Function

Product of Two Numbers in PHP

In this article I wrote a simple program to ask the user to give two numbers and then our program will compute the product of the two numbers given by our user using PHP. The code is very simple and easy to understand you will learn how to use HTML forms to accept and process the values from the user.

My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 

My mobile number here in the Philippines is 09173084360.

Sample Program Output

Program Listing

<?php

error_reporting(0);

$a =$_POST['num1'];

$b =$_POST['num2'];

if (isset($_POST['ok']))

{

$result= $a * $b;

}

if (isset($_POST['clear']))

{

$a="";

$b="";

$result= "";

}

?>

<html><body>

<style>

body {

background-color:lightgreen;

font-family:arial;

font:12px;

}

</style>

<form action="index.php" method="post">

<h3> Product of Two Numbers in PHP </h3>

<br>

Value No. 1 : &nbsp;&nbsp;  <input name="num1" value="<?php echo $a ?>" autofocus required> <br><br>

Value No. 2 : &nbsp;&nbsp;  <input name="num2" value="<?php echo $b ?>" required>

<br><br>

Answer      : &nbsp;&nbsp;&nbsp;&nbsp; &nbsp;&nbsp;&nbsp;  

             <input value="<?php if (isset($result)) echo $result ?>" readonly>

<br><br>

<input type="submit" name="ok" value="Ok" title="Click here to find the product.">

&nbsp;&nbsp;&nbsp;

<input type="submit" name="clear" value="Clear" title="Click here to clear the text box.">

</form>

</body></html>

User Account Information System in PHP and MySQLi

Hi guys in today's article I am glad and happy to to share with you a work of my close friend and fellow software engineer Mr. Raymil Garde he is also a practicing freelance web developer in Bacolod City, Negros Occidental, Philippines. In this program it will allow the user to store, edit and delete the user account in the database using PHP and MySQLi the code is already Object Oriented so it is very organize and easy to understand. I am honored that Mr. Garde allow us to share his work in our website. I hope you will find his work useful. Thank you.

My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 

My mobile number here in the Philippines is 09173084360.

Sample Program Output

DOWNLOAD SOURCECODE HERE

Getline Command in C++

Hi there in this article I would like to share with you how to use getline command in C++. This program is very simple and easy to understand it will ask the users name and address and display the input data in the screen.

My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 

My mobile number here in the Philippines is 09173084360.

Sample Program Output

Program Listing

#include <iostream>

using namespace std;

int main()

{

    string name, address;

    cout << "\n\n";

    cout << "Enter you name : ";

    getline(cin,name);

    cout << "Enter your home address: ";

    getline(cin,address);

    cout << "\n\n";

    cout << "Hi " << name;

    cout << "\n\n";

    cout <<"You present home address is " <<address;

    cout << "\n\n";

    cout << "\tEnd of Program";

    cout << "\n\n";

}

Persons Age Checker in C

In this article I would like to share with you a very simple program that teacher you how to use if - else statement in C. What does the program will do is to ask the persons age and then our program will check if the age of the person is already an adult or still a minor. I wrote this code using CodeBlocks 16.1 as my text editor and Dev C++ as my C compiler. I hope you will find my work useful. Thank you. 

My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 

My mobile number here in the Philippines is 09173084360.

Sample Program Output

Program Listing

/* Persons Age Checker in C */

/* Author  : Mr. Jake R. Pomperada, MAED-IT   */

/* Date    : March 1, 2017  Wednesday         */

/* Tools   : CodeBlocks 16.1                  */

/* Country : Philippines                      */

#include <stdio.h>

int age = 0;

int main()

{

    printf("\n\n");

    printf("\t===== PERSONS AGECHECKER IN C =====");

    printf("\n\n");

    printf("What is your age : ");

    scanf("%d",&age);

    if (age >= 18 ) {

        printf("\n\n");

        printf("At the age of %d you are already an ADULT.",age);

      }

    else {

        printf("\n\n");

        printf("At the age of %d you are still a MINOR.",age);

      }

    printf("\n\n");

    printf("END OF PROGRAM");

    printf("\n\n");

}

Positive and Negative Number Checker in C

Good day in this article I would like to share with you guys a very simple program that I wrote using C as my programming language. I called this simple program positive and negative number checker in C. What program does is to ask the user to give a number and then our program will check and determines whether the given number is a positive or negative number. It uses conditional if statement to achieve the results. I am using CodeBlocks 16.1 in creating this program. I hope you will find my work useful. Thank you.

My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 

My mobile number here in the Philippines is 09173084360.

Sample Program Output

Program Listing

/* Positive and Negative Number Checker in C */

/* Author  : Mr. Jake R. Pomperada, MAED-IT   */

/* Date    : March 1, 2017  Wednesday         */

/* Tools   : CodeBlocks 16.1                  */

/* Country : Philippines                      */

#include <stdio.h>

int num_value = 0;

int main()

{

    printf("\n\n");

    printf("\t===== POSITIVE AND NEGATIVE NUMBER CHECKER IN C =====");

    printf("\n\n");

    printf("Give a Number : ");

    scanf("%d",&num_value);

    if (num_value > 0 ) {

        printf("\n\n");

        printf("The given number %d is a POSITIVE NUMBER.",num_value);

      }

    else if (num_value < 0 ) {

        printf("\n\n");

        printf("The given number %d is a NEGATIVE NUMBER.",num_value);

      }

    else {

        printf("\n\n");

        printf("The given number %d is a ZERO.",num_value);

      }

    printf("\n\n");

    printf("END OF PROGRAM");

    printf("\n\n");

}

Login System With User Account Disabled in PHP and MySQLi

Hi guys in this article I would like to share with you a modified version of my original code that locks the user after three attempts of login in the system by this time I added a functionality to disable the user account in the database by using a Flag in this case the flag is used is the status field in the table if the status = 0 zero it means the user account this disable but if the status = 1 it means the user account is enable. I hope you will find my work useful it has been a long time I was able to solve this problem but here is the complete and right solution to the problem. Thank you very much for visiting my website.

My email address are the following jakerpomperada@gmail.com and jakerpomperada@yahoo.com. 

My mobile number here in the Philippines is 09173084360.

Sample Program Output

Database and Table Structure

Program Listing

<!-- connet_to_database.php

     Author    : Mr. Jake Rodriguez Pomperada, MAED-IT

     Date      : February 26, 2017 Sunday  6:29 AM

     Tools     : PHP, MySQL, Google Chrome and Sublime Text 3

     Emails    : jakerpomperada@gmail.com and jakerpomperada@yahoo.com

     Country of Origin : Philippines

     Nature of Code : Security Routine

     Code Licence : Open Source 

-->

<?php

     define('_HOST_NAME','localhost');

     define('_DATABASE_NAME','login');

     define('_DATABASE_USER_NAME','root');

     define('_DATABASE_PASSWORD','');

     $MySQLiconn = new MySQLi(_HOST_NAME,_DATABASE_USER_NAME,_DATABASE_PASSWORD,_DATABASE_NAME);

 

if($MySQLiconn->connect_errno)

{

die("ERROR : -> ".$MySQLiconn->connect_error);

}

 

?>

<!-- login.php

     Author    : Mr. Jake Rodriguez Pomperada, MAED-IT

     Date      : February 26, 2017 Sunday  6:29 AM

     Tools     : PHP, MySQL, Google Chrome and Sublime Text 3

     Emails    : jakerpomperada@gmail.com and jakerpomperada@yahoo.com

     Country of Origin : Philippines

     Nature of Code : Security Routine

     Code Licence : Open Source 

-->

<html>

<head>

 <title>

   Login System With User Account Disabled in PHP and MySQLi

  </title>

 </head> 

<?php

include 'connect_to_database.php'; //connect the connection page

if(empty($_SESSION)) // if the session not yet started 

   session_start();

if(isset($_SESSION['username'])) { // if already login

   header("location: home.php"); // send to home page

   exit; 

}

?>

<html>

<head></head>

<body>

<style>

body {

    background-color: lightgreen;

    font-family:arial;

    font-size:20px;

}

   input, button, select, option, textarea {

    font-size: 100%;

}

</style>

<br><br>

<h2> Login System With User Account Disabled in PHP and MySQLi OOP Version </h2>

<h4> Created By: Mr. Jake Rodriguez Pomperada, MAED-IT</h4>

<br>

<form action = 'login_process.php' method='POST'>

  Enter   Username:   &nbsp;

 <input type="text" name="username" />  <br><br>

    Enter Password: &nbsp;

 <input type="password" name="password" />

<br> <br>

<input type = "submit" name="submit" value="Ok" />  

</form>

</body>

</html>

<!-- login_process.php

     Author    : Mr. Jake Rodriguez Pomperada, MAED-IT

     Date      : February 26, 2017 Sunday  6:29 AM

     Tools     : PHP, MySQL, Google Chrome and Sublime Text 3

     Emails    : jakerpomperada@gmail.com and jakerpomperada@yahoo.com

     Country of Origin : Philippines

     Nature of Code : Security Routine

     Code Licence : Open Source 

-->

<html>

 <head>

 <title>

   Login System With User Account Disabled in PHP and MySQLi

  </title>

 </head> 

<body>

<style>

body {

    background-color: lightgreen;

    font-family:arial;

    font-size:20px;

}

</style>

<?php

error_reporting(0);

include 'connect_to_database.php'; //connect the connection page

  

if(empty($_SESSION)) // if the session not yet started 

   session_start();

if(!isset($_POST['submit'])) { // if the form not yet submitted

   header("Location: login.php");

   exit; 

}

      $attempt = 1;

      $myusername = $_POST['username'];

      $mypassword = $_POST['password'];

       

// query to get the users lastname and firstname to be display in the main page

// Query if the user account is not disabled

$test_query2 = "SELECT * FROM users WHERE username = '$myusername' and password = '$mypassword' and status = 1 ";

// Query if the user account is  disabled

$test_query3 = "SELECT * FROM users WHERE username = '$myusername' and password = '$mypassword' and status = 0 ";

     

$disable_account = "UPDATE users SET status = 0 WHERE username = '$myusername' ";

$res2 = $MySQLiconn->query($test_query3);

// Query to check if the user account is already been disable by the system

if($res2->num_rows > 0) {

     header("Location: disabled.php");

     }

$res = $MySQLiconn->query($test_query2);

          if($res->num_rows > 0) {

                              while($row=$res->fetch_array()) {

                              $_SESSION['username'] = $_POST['username'];

                              $_SESSION['lastname'] = $row['lastname'];

                              $_SESSION['firstname']= $row['firstname'];

                              header("Location: home.php");

                              exit;

                         }    

            

               } else {

                         $number = $_SESSION['number'];

                         $number++;

                         $_SESSION['number'] = $number;

                         echo "<br><br>";

                         echo "<h1> Access Denied !!! Try Again </h1>";    

                         echo "Attempt Number   : <font color='red'> $number </font>";              

                         echo "<br><br>";

                         echo "<a href='login.php'>Return To Login Page</a> " ;

                         echo "</font></font>";

               

                    if ($number>2) {

                         $res3 = $MySQLiconn->query($disable_account);

                         header("Location: disabled.php");

                         exit;

                    }

          }

               

?>

</body>

</html>

<!-- home.php

     Author    : Mr. Jake Rodriguez Pomperada, MAED-IT

     Date      : February 26, 2017 Sunday  6:29 AM

     Tools     : PHP, MySQL, Google Chrome and Sublime Text 3

     Emails    : jakerpomperada@gmail.com and jakerpomperada@yahoo.com

     Country of Origin : Philippines

     Nature of Code : Security Routine

     Code Licence : Open Source 

-->

<?php

include 'connect_to_database.php'; //connect the connection page

if(empty($_SESSION)) // if the session not yet started 

   session_start();

if(!isset($_SESSION['username'])) { //if not yet logged in

   header("Location: login.php");// send to login page

   exit;

} 

?>

<html>

<body>

<style>

body {

    background-color: lightgreen;

    font-family:arial;

    font-size:20px;

    }

input, button, select, option, textarea {

    font-size: 100%;

}

</style>

<br>

<H2> Welcome Page </H2>

<br>

Welcome  <b> <?php echo $_SESSION['firstname']. " ".$_SESSION['lastname']."."; ?>  </b>

<br><br>

 <a href="logout.php">Logout</a> 

</body>

</html> 

<!-- disabled.php

     Author    : Mr. Jake Rodriguez Pomperada, MAED-IT

     Date      : February 26, 2017 Sunday  6:29 AM

     Tools     : PHP, MySQL, Google Chrome and Sublime Text 3

     Emails    : jakerpomperada@gmail.com and jakerpomperada@yahoo.com

     Country of Origin : Philippines

     Nature of Code : Security Routine

     Code Licence : Open Source 

-->

<html>

 <head>

 <title> Disabled User Account </title>

 </head>

<body>

<style>

body {

    background-color: lightgreen;

    font-family:arial;

    font-size:20px;

}

</style>

<?php

         

 $message1= "Sorry your user account is already been  <font color='red'>DISABLED</font>.";

 $message2= "The system will be locked.";

 $message3 = "Kindly send an email to the programmer for assistance at 

           <font color='blue'> jakerpomperada@gmail.com </font>.";

             

 echo "<br><br>"; 

 echo "$message1";

 echo "<br>";

 echo "<h1><font color='red'> $message2 </font></h1>";

 echo "<br>"; 

 echo "<h3>$message3</h3>";

 echo "<br>"; 

 echo "&nbsp;&nbsp;&nbsp;&nbsp;<a href='logout.php'>CLOSE</a>";

?>

   </body>

</html>

<!-- disabled.php

     Author    : Mr. Jake Rodriguez Pomperada, MAED-IT

     Date      : February 26, 2017 Sunday  6:29 AM

     Tools     : PHP, MySQL, Google Chrome and Sublime Text 3

     Emails    : jakerpomperada@gmail.com and jakerpomperada@yahoo.com

     Country of Origin : Philippines

     Nature of Code : Security Routine

     Code Licence : Open Source 

-->

<html>

 <head>

 <title> Disabled User Account </title>

 </head>

<body>

<style>

body {

    background-color: lightgreen;

    font-family:arial;

    font-size:20px;

}

</style>

<?php

         

 $message1= "Sorry your user account is already been  <font color='red'>DISABLED</font>.";

 $message2= "The system will be locked.";

 $message3 = "Kindly send an email to the programmer for assistance at 

           <font color='blue'> jakerpomperada@gmail.com </font>.";

             

 echo "<br><br>"; 

 echo "$message1";

 echo "<br>";

 echo "<h1><font color='red'> $message2 </font></h1>";

 echo "<br>"; 

 echo "<h3>$message3</h3>";

 echo "<br>"; 

 echo "&nbsp;&nbsp;&nbsp;&nbsp;<a href='logout.php'>CLOSE</a>";

?>

   </body>

</html>

users.sql

-- phpMyAdmin SQL Dump

-- version 4.5.1

-- http://www.phpmyadmin.net

--

-- Host: 127.0.0.1

-- Generation Time: Feb 25, 2017 at 11:42 PM

-- Server version: 10.1.16-MariaDB

-- PHP Version: 5.6.24

SET SQL_MODE = "NO_AUTO_VALUE_ON_ZERO";

SET time_zone = "+00:00";

/*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT */;

/*!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS */;

/*!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION */;

/*!40101 SET NAMES utf8mb4 */;

--

-- Database: `login`

--

-- --------------------------------------------------------

--

-- Table structure for table `users`

--

CREATE TABLE `users` (

  `id` int(11) NOT NULL,

  `username` varchar(100) NOT NULL,

  `password` varchar(100) NOT NULL,

  `lastname` varchar(200) NOT NULL,

  `firstname` varchar(200) NOT NULL,

  `status` varchar(1) NOT NULL

) ENGINE=InnoDB DEFAULT CHARSET=latin1;

--

-- Dumping data for table `users`

--

INSERT INTO `users` (`id`, `username`, `password`, `lastname`, `firstname`, `status`) VALUES

(1, 'jake', 'jake', 'POMPERADA', 'JAKE', '1'),

(2, 'jacob', 'jacob', 'POMPERADA', 'JACOB SAMUEL', '0'),

(3, 'allie', 'allie', 'POMPERADA', 'MA. JUNALLIE', '1'),

(4, 'iya', 'iya', 'POMPERADA', 'JULIANNA RAE', '0'),

(5, 'bill', 'bill', 'GATES', 'BILL', '0'),

(6, 'peter', 'peter', 'NORTON', 'PETER', '0');

--

-- Indexes for dumped tables

--

--

-- Indexes for table `users`

--

ALTER TABLE `users`

  ADD PRIMARY KEY (`id`);

--

-- AUTO_INCREMENT for dumped tables

--

--

-- AUTO_INCREMENT for table `users`

--

ALTER TABLE `users`

  MODIFY `id` int(11) NOT NULL AUTO_INCREMENT, AUTO_INCREMENT=7;

/*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT */;

/*!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS */;

/*!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;

DOWNLOAD SOURCE CODE HERE