A very simple program that will ask the user to give a string and then the program will check and determine if the given string is a palindrome or not using pointers in C.
programming projects, thesis and capstone projects, IT consulting
work, computer tutorials, and web development work kindly contact me in the following email address for further details. If you want to advertise on my website kindly contact me also in my email address also. Thank you.
My email address is the following jakerpomperada@gmail.com, jakerpomperada@aol.com, and jakerpomperada@yahoo.com.
My mobile number here in the Philippines is 09173084360.
My telephone number at home here in Bacolod City, Negros Occidental Philippines is +63 (034) 4335675.
My personal website is http://www.jakerpomperada.com
My personal website is http://www.jakerpomperada.com
Sample Program Output
Program Listing
#include <stdio.h>
void stringUpr(char *s);
void stringLwr(char *s);
int main()
{
char string[100];
char *ptr,*rev;
printf("\n\n");
printf("\tPalindrome Program ");
printf("\n\n");
printf("\tGive a String : ");
gets(string);
ptr=string;
stringUpr(ptr);
while(*ptr!=NULL){
++ptr;
}
--ptr;
for(rev=string; ptr>=rev;){
if(*ptr == *rev)
{
--ptr;
rev++;
}
else
break;
}
if(rev>ptr) {
printf("\n\n");
stringUpr(string);
printf("\tThe given string %s is Palindrome.",string);
}
else {
printf("\n\n");
stringUpr(string);
printf("\tThe given string %s is Not a Palindrome.",string);
}
printf("\n\n");
printf("\tEND OF PROGRAM");
printf("\n\n");
}
void stringLwr(char *s)
{
int i=0;
while(s[i]!='\0')
{
if(s[i]>='A' && s[i]<='Z'){
s[i]=s[i]+32;
}
++i;
}
}
void stringUpr(char *s)
{
int i=0;
while(s[i]!='\0')
{
if(s[i]>='a' && s[i]<='z'){
s[i]=s[i]-32;
}
++i;
}
}