Leap Year Program Using unless Using Ruby

Write a program that will ask the user to give a year and then the program will determine if the given year is a leap year or not a leap year using unless statement and display the result on the screen.

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Sample Program Output

Program Listing

# leap.rb

# Author   : Jake Rodriguez Pomperada,BSCS,MAED-IT

# Date     : June 4, 2019   Tuesday  5:19 AM

# Address  : Bacolod City, Negros Occidental

# Tools    : Eclipse IDE and Ruby Version 2.6.3

# Location : Bacolod City, Negros Occidental  

# Website  : http://www.jakerpomperada.com

# Emails   : jakerpomperada@gmai.com and jakerpomperada@yahoo.com

puts "\n\n"

print "\tLeap Year Program Using unless";

puts "\n\n"

print "\tGive a Year  : ";

year = gets.chomp

year = year.to_i;

print "\n";

print "\t===== DISPLAY RESULT ====="

print "\n\n";

unless (((year % 4 == 0) && (year % 100 !=0)) || (year % 400==0))

  print("\tThe give year #{year} is NOT a LEAP year.\n\n");

else    

  print("\tThe give year #{year} is a LEAP year.\n\n");

end  

print "\tEND OF PROGRAM";

print "\n\n";