Console Menu in Python

Create a menu-driven program that will allow only to accept a number and provide an error message if the wrong option is selected from the menu.

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Program Listing

print();

def print_menu():

    print(20 * "-", "MENU", 20 * "-");

    print("\t1. Menu Option 1");

    print("\t2. Menu Option 2")

    print("\t3. Menu Option 3");

    print("\t4. Menu Option 4");

    print("\t5. Exit");

    print(45 * "-");

loop = True

while loop:

    print_menu()

    try:

       choice = int(input("\tEnter your choice [1-5]: "));

    except ValueError:

        print("\tIt's not a number! Try again");

    if choice == 1:

        print();

        print("\tMenu 1 has been selected");

    elif choice == 2:

        print();

        print("\tMenu 2 has been selected");

    elif choice == 3:

        print();

        print("\tMenu 3 has been selected");

    elif choice == 4:

        print();

        print("\tMenu 4 has been selected");

    elif choice == 5:

        print();

        print("\tMenu 5 has been selected ");

        print("\tQuit Program and Return to Windows");

        loop = False

    else:

         print("\tWrong option selection. Select Again.");