Shell Sort Program in C

 A simple shell sort program that I wrote using C programming language.

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Program Listing

/* shell_sort.c

   Author   : Mr. Jake Rodriguez Pomperada,MAED-IT, MIT

   Tool     : Dev C++ 5.11

   Date     : August 15, 2021   Sunday  4:29 PM

   Websites  : www.jakerpomperada.com and www.jakerpomperada.blogspot.com

   Email    :jakerpomperada@gmail.com

   Location : Bacolod City, Negros Occidental, Philippines

*/

#include <stdio.h>

#include <stdlib.h>

void shellsort(int arr[], int num);

int main()

{

 int items[1000], num=0,min=0,loc=0;

 int c=0, b=0,change=0,j=0,temp=0;

 system("cls");

 printf("\n\n");

 printf("\tShell Sort Program in C");

 printf("\n\n");

 printf("\tHow many items? : ");

 scanf("%d", &num);

 printf("\n\n");

 for (c= 0; c < num; c++) {

    printf("\tEnter item no. %d: ", c+1);

    scanf("%d", &items[c]);

 }

printf("\n\n");

printf("\tOriginal Arrangement of Numbers");

printf("\n\n");

 for ( c = 0 ; c < num ; c++ ) {

   printf("\t%d ",items[c]);

 }

 shellsort(items, num);

 printf("\n\n");

 printf("\tAsceding Order of Numbers");

 printf("\n\n");

 for ( c = 0 ; c < num ; c++ ) {

 printf("\t%d ", items[c]);

 }  

printf("\n\n");

printf("\tEnd of Program");

printf("\n\n");

system("pause");

}

void shellsort(int arr[], int num)

{

    int i, j, k, tmp;

    for (i = num / 2; i > 0; i = i / 2)

    {

        for (j = i; j < num; j++)

        {

            for(k = j - i; k >= 0; k = k - i)

            {

                if (arr[k+i] >= arr[k])

                    break;

                else

                {

                    tmp = arr[k];

                    arr[k] = arr[k+i];

                    arr[k+i] = tmp;

                }

            }

        }

    }

}