I wrote this program to ask the user to give a series of numbers and then number to be search using linear search algorithm in C programming language.
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Sample Program Output
Program Listing
#include <stdio.h>
int main()
{
int array[100], search=0, c=0, n=0;
printf("\n");
printf("\tLinear Search in C Language");
printf("\n\n");
printf("\tEnter number of elements : ");
scanf("%d", &n);
printf("\tEnter %d integer(s)\n", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
printf("\tEnter a number to search\n");
scanf("%d", &search);
for (c = 0; c < n; c++)
{
if (array[c] == search)
{
printf("%d is present at location %d.\n", search, c+1);
break;
}
}
if (c == n) {
printf("%d isn't present in the array.\n", search);
}
printf("\n");
printf("\tEnd of Program");
printf("\n");
}
int main()
{
int array[100], search=0, c=0, n=0;
printf("\n");
printf("\tLinear Search in C Language");
printf("\n\n");
printf("\tEnter number of elements : ");
scanf("%d", &n);
printf("\tEnter %d integer(s)\n", n);
for (c = 0; c < n; c++)
scanf("%d", &array[c]);
printf("\tEnter a number to search\n");
scanf("%d", &search);
for (c = 0; c < n; c++)
{
if (array[c] == search)
{
printf("%d is present at location %d.\n", search, c+1);
break;
}
}
if (c == n) {
printf("%d isn't present in the array.\n", search);
}
printf("\n");
printf("\tEnd of Program");
printf("\n");
}
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