Running Sum of Numbers Using Ordinal Indicators in C++

I wrote this simple program to demonstrate how to write a running sum of number using ordinal numbers in C++ programming language.

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Sample Program Output

Program Listing

ordinal.cpp

// ordinal.cpp

// Jake Rodriguez Pomperada

// May 26, 2020      Tuesday    10:51 PM

 #include <iostream>

 #include <string>

 using namespace std;

 

string ordinal(int i)

{

int mod100 = 0, mod10 = 0;

mod100 = (i % 100);

mod10 = (i % 10);

 

if (mod10 == 1 && mod100 != 11) {

return "st";

} else if (mod10 == 2 && mod100 != 12) {

 return "nd";

}

else if (mod10 == 3 && mod100 != 13) {

return "rd";

} else {

return "th";

 }

}

 int main()

 {

 

   int num_items = 0, sum = 0, num;

   

   cout <<"\n\n";

   cout <<"\tRunning Sum of Numbers Using Ordinal Indicators in C++";

   cout <<"\n\n";

   cout << "\tHow many items: ";

   cin >> num_items;

   for (int i = 1; i <= num_items; ++i)

  {

    cout << "\tGive value in the " << i << ordinal(i) << " item: ";

    cin >> num;

    sum += num;

   cout << "\tThe running sum is: " << sum << '\n';

   }

   cout <<"\n";

   cout <<"\tEnd of the Program";

   cout <<"\n";

 }