Leap Year Checker in Python

Write  a program that will ask the user to input a year and then, the program will check if the given year is a leap year or not a leap year, and display the result on the screen.

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Program Listing

def my_program():

   print()

   print("\tLEAP YEAR CHECKER")

   print()

   year = int(input("\tGive a Year: "))

   print()

   if (year % 4) == 0:

       if (year % 100) == 0:

           if (year % 400) == 0:

               print("\t{0} is a leap year".format(year))

           else:

               print("\t{0} is not a leap year".format(year))

       else:

           print("\t{0} is a leap year".format(year))

   else:

       print("\t{0} is not a leap year".format(year))

   print();

   repeat = input('\tDo you want to continue ? (Y/N) : ')

   if repeat.upper() == "N":

       print()

       print("\tEND OF PROGRAM")

       quit

   if repeat.upper() == "Y":

       my_program()

if __name__ == '__main__':

       my_program()