Leap Year Checker Using Function in Python

Presently learning how to program python for my book writing project and to spend my free time in a productive way.

I am currently accepting programming work, IT projects, school and application development, programming projects, thesis and capstone projects, IT consulting.

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Here in Bacolod I also accepting computer repair, networking and Arduino Project development at a very affordable price.

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Problem

Write a program that will ask the user to give the year and then

the program will check and determine if the given year by the user is a leap year or not using the function. 

The program also asks the user if the user will continue using the program or not. If the user chooses Y for yes the program will run again but if the user chooses N for no the program

will display a thankful message and return to the operating system.

Sample Program Output

Program Listing

# leap_year.py

# Jake R. Pomperada

# February 25, 2019    Tuesday

# Bacolod City, Negros Occidental

def leap_year(year):

    if year % 4 == 0 and year % 100 != 0:

        print("\tThe year %d is a Leap Year" % year)

    elif year % 100 == 0:

        print("\tThe year %d is not a Leap Year" % year)

    elif year % 400 == 0:

        print("\tThe year %d is a Leap Year" % year)

    else:

        print("\tThe year %d is not a Leap Year" % year)

def my_program():

    print();

    print("\tLeap Year Checker Using Function");

    print();

    a= int(input("\tGive a Year : "));

    display = a;

    print();

    leap_year(display);

    print();

    repeat = input('\tDo you want to continue ? (Y/N) : ')

    if repeat.upper() == "N":

        print()

        print("\tThank You For Using This Program.")

        print();

        print("\tEND OF PROGRAM");

        quit

    if repeat.upper() == "Y":

        my_program()

if __name__ == '__main__':

    my_program()