Friday, September 6, 2019

Odd and Even Number Checker Using Structures Using Golang


Write a program that will ask the user to give a number and then the program will check if the given number is an even or odd number and then display the results on the screen using structures using Golang programming language.

I am currently accepting programming work, IT projects, school and application development, programming projects, thesis and capstone projects, IT consulting work, computer tutorials, and web development work kindly contact me in the following email address for further details.  If you want to advertise on my website kindly contact me also in my email address also. Thank you.

My email address is the following jakerpomperada@gmail.com, jakerpomperada@aol.com, and jakerpomperada@yahoo.com.

My mobile number here in the Philippines is 09173084360.

My telephone number at home here in Bacolod City, Negros Occidental Philippines is  +63 (034) 4335675.

Here in Bacolod I also accepting computer repair, networking and Arduino Project development at a very affordable price.

My personal website is http://www.jakerpomperada.com\


Sample Program Output


Program Listing


/* odd_even.go
   Author   : Mr. Jake Rodriguez Pomperada, MAED-IT
   Date     : August 6, 2019  Thursday  4:37 PM
   Location : Bacolod City, Negros Occidental
   Website  : http://www.jakerpomperada.com
   Emails   : jakerpomperada@gmail.com and jake_pomperada@tup.edu.ph
 */

package main

import "fmt"

type check_even_odd struct {
a int32
}


func main(){
var num_value check_even_odd
fmt.Print("\n")
fmt.Print("\tOdd and Even Number Checker Using Structures")
fmt.Print("\n\n")
fmt.Print("\tKindly give a number? ")
fmt.Scanln(&num_value.a)
if num_value.a % 2 ==0 {
fmt.Print("\n")
fmt.Print("\tThe given number ")
fmt.Printf("%d",num_value.a)
fmt.Print(" is an Even Number.")
} else {
fmt.Print("\n")
fmt.Print("\tThe given number ")
fmt.Printf("%d",num_value.a)
fmt.Print(" is an Odd Number.")
}
fmt.Print("\n\n")
fmt.Print("\tEnd of Program")
fmt.Print("\n")
}



No comments:

Post a Comment